Question

If 425 joules are absorbed from the higher temperature reservoir and 295 joules of that is passed onto the lower temperature reservoir, how much work has been done by the system?

a.130 joules


b.151 joules


c.187 joules


d.98 joules

Answer 1

Its A just subtract them 425-295=130

Answer 2

Option (a)

Step-by-step explanation:

A heat engine is a device which converts heat energy into some useful work.

The work done is defined as the difference in heat absorbed from the reservoir at high temperature and the heat exhaust to the reservoir at low temperature.

W = Q1 - Q2

Where, Q1 is the heat absorbed and Q2 is the heat exhausted

W = 425 - 295

W = 130 joule