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What is the melting point of a solution in which 2.5 grams of sodium chloride is added to 230 mL of water?

User Medo Medo
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To get the melting point of a solution so, we will use this formula:

ΔT = - mKf

when:

m is molality of the solution

Kf is cryoscopic constant of water = 1.86 C/m

and ΔT is the change in melting point (T2 - 0 °C)

so, now we need to calculate the molality to substitute:

when the molality = moles NaCl / Kg of water

and when moles NaCl = mass / molar mass

= 2.5 g / 58 g/mol

= 0.043 mol
∴ Kg water = volume *density /1000

= 230 mL * 1 g/mL / 1000

= 0.23 Kg
∴ molality = 0.043 / 0.23 =0.187 M

by substitution:

T2-0°C = - 0.187 * 1.86

∴T2 = - 0.348 °C

User YMMD
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