Register
How many atoms of ca-46 would be found in a 25.0 g sample of naturally occurring calcium ?
170k views
1 vote
How many atoms of ca-46 would be found in a 25.0 g sample of naturally occurring calcium ?

User Sid Barrack
by
8.2k points

1 Answer

2 votes
The number of ca-46 atoms found in 25.0 g sample is calculated as follows

find the moles of Ca= 25/46 =0.543 moles

by use of Avogadro law
1 mole = 6.02 x10^23 atoms what about 0.543 moles

= 0.543moles/1mole x (6.02x10^23)atoms = 3.27 x10 ^23 atoms
User Fuco
by
8.5k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

Compare and contrast an electric generator and a battery??
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Why is gold preferred as a superior metal over silver and bronze?
What is the evidence of a chemical reaction when the fireworks go off
Link Copied!