Question

Hey guys please help me please!! :)

Answer 1

A quadratic equation can be written as:


`ax^2 + bx + c = 0`

First, let's factor out a 3 from both terms on the left:


`x^2 + 6x + 5 = 0`

Move the constant to the other side:


`x^2 + 6x = -5`

Now, to complete the square, we need to find:


`( (b)/(2))^2`


`( (6)/(2))^2=9`

Now add this value to both sides of the equation:


`3(x^2 + 6x + 9) = 4`

Factor:


`(x+3)^2=4`

Find the square root of both sides:

x + 3 = ±2

x = -5 and x = -1