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Which equation has the same solution 2x²+16x-10=0 a.(x+4)²= -3 b.(x+4)²= -11 C..(x+4)²= 13 d.(x+4)²= 21
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Which equation has the same solution 2x²+16x-10=0

a.(x+4)²= -3
b.(x+4)²= -11
C..(x+4)²= 13
d.(x+4)²= 21

User Protozoid
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1 Answer

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2x²+16x-10=0

is equivalent to: (divide by two)

x²+8x-5=0

The answer is d. (x+4)²= 21

Because,

(x+4)²= 21

x² + 8x +16 = 21

x² + 8x +16 -21= 0

x² + 8x - 5= 0




User Robocat
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