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What is the pressure of 1.20 moles of SO2 gas in a 4L container at 30 degrees celsius

2 Answers

7 votes

Answer:

7.45 atm

Step-by-step explanation:

Let suppose the Gas is acting Ideally, Then According to Ideal Gas Equation,

P V = n R T

Solving for P,

P = n R T / V ----- (1)

Data Given;

Moles = n = 1.20 mol

Volume = V = 4 L

Temperature = T = 30 + 273 = 303 K

Gas Constant = R = 0.08206 atm.L.mol⁻¹.K⁻¹

Putting Values in Eq.1,

P = (1.20 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 303 K) ÷ 4 L

P = 7.45 atm

User BPL
by
5.6k points
6 votes
Let suppose the Gas is acting Ideally, Then According to Ideal Gas Equation,

P V = n R T
Solving for P,
P = n R T / V ----- (1)
Data Given;

Moles = n = 1.20 mol

Volume = V = 4 L

Temperature = T = 30 + 273 = 303 K

Gas Constant = R = 0.08206 atm.L.mol⁻¹.K⁻¹

Putting Values in Eq.1,

P = (1.20 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 303 K) ÷ 4 L

P = 7.45 atm
User Jjed
by
6.0k points