Question

suppose that the function V = 40x to the 2nd -500× + 5000 describes the value of a car from 1960 to 2012. What year did the car have the least value? (x = 0 is 1960)

Answer 1

We have the next function

`V=40x^2-500x+5000`

In 1960, x=0

`V=5000`

In 1965, x=5

`V=3500`

In 1966, x=6

`V=3440`

In 1967, x=7

`V=3460`

In 1968, x=8

`V=3560`

As we can see the year with the least value is 1966