Question

What are some cofunction identities for the following expressions:

f(x)=sinx and g(x)=cos(x-pi/2)

Answer 1

This means that you start with g ( x ) = cos ( x ) Substitute x = π 2 into g ( x ) g ( π 2 ) = cos ( π 2 ) g ( π 2 ) = 0 We know that g ( π 2 ) = 0 , therefore, we can substitute 0 into f ( x ) = sin ( x ) : f ( 0 ) = sin ( 0 ) f ( 0 ) = 0This means that you start with g ( x ) = cos ( x ) Substitute x = π 2 into g ( x ) g ( π 2 ) = cos ( π 2 ) g ( π 2 ) = 0 We know that g ( π 2 ) = 0 , therefore, we can substitute 0 into f ( x ) = sin ( x ) : f ( 0 ) = sin ( 0 ) f ( 0 ) = 0This means that you start with g ( x ) = cos ( x ) Substitute x = π 2 into g ( x ) g ( π 2 ) = cos ( π 2 ) g ( π 2 ) = 0 We know that g ( π 2 ) = 0 , therefore, we can substitute 0 into f ( x ) = sin ( x ) : f ( 0 ) = sin ( 0 ) f ( 0 ) = 0