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The electrical force on a 2-c charge is 60 n. the electric field where the charge is located is

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The electrical force acting on a charge q immersed in an electric field is equal to

F=qE
where
q is the charge
E is the strength of the electric field

In our problem, the charge is q=2 C, and the force experienced by it is
F=60 N
so we can re-arrange the previous formula to find the intensity of the electric field at the point where the charge is located:

E= (F)/(q)= (60 N)/(2 C)=30 N/C
User Amesh
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