Question

What are the sine, cosine, and tangent of 11 pi over 6 radians? sin θ = square root 3 over 2; cos θ = 1 over 2; tan θ = square root 3 over 3 sin θ = negative square root 3 over 2; cos θ = 1 over 2; tan θ = negative square root 3 over 3 sin θ = negative 1 over 2; cos θ = square root 3 over 2; tan θ = negative square root 3 over 3 sin θ = 1 over 2; cos θ = negative square root 3 over 2; tan θ = negative square root 3 over 3

Answer 1

sin θ = negative 1 over 2; cos θ = square root 3 over 2; tan θ = negative square root 3 over 3

Explanation:

Answer 2

we know that

θ=11 pi /6 radians-----> 11*180/6----> 330°
330°----> belong to the IV quadrant
so
cos θ----> is positive
sin θ----> is negative
tan θ----> is negative

330°-----> 360°-330°---> 30°

sin 30°------> 1/2
sin θ=-1/2-----> remember that sin θ is negative

cos 30°------> √3/2
cos θ=√3/2

tan 30°------> (1/2)/(√3/2)----> √3/3
tan θ=-√3/3-------> remember that tan θ is negative

the answer is
sin θ = negative 1 over 2; cos θ = square root 3 over 2; tan θ = negative square root 3 over 3