Question

Calculate the molarity of a solution prepared by dissolving 11.5 g naoh in enough water to make 1.5 l of solution. 1. 7.6 m 2. 2.3 m 3. 0.19 m 4. 0.43 m

Answer 1

The molarity of the solution prepared by dissolving 11.5 g of NaOH in enough water to make 1.5 L of solution is 0.19 M.

Step-by-step explanation:

To calculate the molarity of a solution, we need to first convert the mass of the solute to moles. The molar mass of NaOH is 40.0 g/mol.

Number of moles of NaOH = 11.5 g / 40.0 g/mol = 0.2875 mol

Next, we need to calculate the volume of the solution in liters.

Volume of solution = 1.5 L

Finally, we can calculate the molarity by dividing the number of moles of solute by the volume of the solution in liters.

Molarity = 0.2875 mol / 1.5 L = 0.19 M

Therefore, the molarity of the solution prepared by dissolving 11.5 g of NaOH in enough water to make 1.5 L of solution is 0.19 M.

Answer 2

Answer: The molarity of the solution is 0.19 M

Step-by-step explanation:

To calculate the molarity of the solution, we use the equation given as:

`\text{Molarity}=\frac{\text{Mass of solute(in grams)}}{\text{Molar mass of solute(in g/mol)}* \text{Volume of solution (in L)}}`

We are given:

Mass of NaOH = 11.5 g

Molar mass of NaOH =
`[23+16+1]g/mol=40g/mol`

Volume of the solution = 1.5 Liters

Putting values in above equation, we get:

`\text{Molarity of solution}=(11.5g)/(40g/mol* 1.5L)=0.19mol/L=0.19M`

Hence, the molarity of the solution is 0.19 M