Question

A sample of gas occupies a volume of 445 mL at a temperature of 274 K. At what temperature will this sample of gas occupy a volume of 499 mL? Show all of the work used to solve this problem.

Answer 1

Answer : The final temperature of gas will be, 307.25 K

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

`V\propto T`

or,

`(V_1)/(V_2)=(T_1)/(T_2)`

where,

`V_1` = initial volume of gas = 445 ml

`V_2` = final volume of gas = 499 ml

`T_1` = initial temperature of gas = 274 K

`T_2` = final temperature of gas = ?

Now put all the given values in the above formula, we get the final temperature of the gas.

`(445ml)/(499ml)=(274K)/(T_2)`

`T_2=307.25K`

Therefore, the final temperature of gas will be, 307.25 K

Answer 2

The temperature that the sample of gas occupy a volume of 499ml is calculated using Charles law formula
that is V1/T1 = V2/T2
V1= 445 ml
T1= 274 k
V2 = 499 ml
T2= ?

from equation above T2 = T1V2/ V1
= 274 k x 499 ml/445ml = 307.25 k