Question

An ideal gas is kept at constant volume of 2.00 L as its temperature is increased, raising the pressure from 15.0 kPa to 30.0 kPa. What work is performed by or on the gas during this process?

A) 4.00 J performed on the gas

B) 0 J

C) 30.0 J performed on the gas

D) 30.0 J performed by the gas

Answer 1

The correct answer is:
B) 0 J

Let's see why. The work done by the gas is equal to

`W=p \Delta V`
where
p is the pressure

`\Delta V` is the variation of volume of the gas.

However, the problem says that the volume is kept constant (2.0 L), so the variation of volume is zero:
`\Delta V=0`, and the work done is zero as well.