Question

136 grams of barium sulfate are used to make a 2.5 M solution. How many liters of water are needed?

Answer 1

Answer: 0.23 L

Explanation: Molarity of solution is defined as the number of moles of solute dissolved per liter of the solution.

Formula used :

`Molarity=(n)/(V_s)`

where,

n= moles of solute

`n=Moles=\frac{\text{Given mass}}{\text{Molar mass}}=(136g)/(233g/mol)=0.58moles`

`V_s` = volume of solution in L

Now put all the given values in the formula of molarity, we get

`2.5M=(0.58moles)/(V_s)`

`V_s=0.23L`

Therefore, the volume of solution in Liters is 0.23.

Answer 2

The number liters that are needed to make 2.5 m solution of BaSO4 is calculated as follows
find moles of BaSO4 = moles = mass/molar mass
= 64g/ 233.4 g/mol= 0.583 moles

volume of water = moles/ molarity
= 0.583 /2.5 = 0.233 L