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The following graph of f(x) = x2 has been shifted into the form f(x) = (x − h)2 + k: a parabola with a vertex of 4, negative 2

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V(4,-2)

In the vertex form, the h value is the x and the k value is the y.
So if the vertex (4,-2) is also (h,k)

You can just simply replace the h and k in (x-h)^2+k.
Which gives us...
f(x)=(x-4)^2-2.

User SANDHYA
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