Question

During the phosphatase experiment you will use a 1% w/v of phenolphthalein di-phosphate (PPP). How much PPP do you need to make 750ml of the solution if you only have 25g and you know that the MW of PPP is 478 g/mole

Answer 1

Step-by-step explanation:

1 % w/v of phenolphthalein di-phosphate (PPP)

will contain 1 gram of phenolphthalein di-phosphate (PPP) in 100 mL of solution

750 mL solution will contain 7.5 g of PPP

750 mL solution will contain 7.5 / 478 moles of PPP

750 mL solution will contain .0157 moles of PPP

So 7.5 g of PPP or .0157 mole of PPP will be needed .