Question

Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M

Answer 1

`= \mathbf{C_3H_6O}`

Step-by-step explanation:

From the given information, since the molecular mass of the ion M+ is not given;

Let's assume M+ = 58.0423

So, by applying the 13th rule;

we will need to divide the mass by 13, after dividing it;

The quotient n = no. of carbon; &

The addition of the quotient (n) with the remainder r = no. of hydrogen.

So;

`(58)/(13)= 4 \ remainder \ 6`

So;

`C_nH_(n+r) = C_4H_(4+6)`

`= C_4H_(10)`

From the given information; we have oxygen present, so since the mass of oxygen = 16, we put oxygen in the molecular formula by removing
`CH_4`. Also, since the mass is an even number then Nitrogen is 0.

So, we have:

`= \mathbf{C_3H_6O}`