Question

The probability a student at Jamal's school is in the band is 0.20. Jamal wants to estimate the probability that in 3 randomly selected students, at least 2 are in the band.

To do this, he uses a simulation. He lets 1 represent a student who is in the band and 2, 3, 4, or 5 represent a student who is not in the band. He then uses a computer to randomly generate 3 random numbers from 1 to 5 twenty times. The results of these 20 trials are shown in this list.

233, 113, 131, 244, 414,344, 412, 132, 554, 454,334, 235, 125, 412, 254,232, 221, 342, 333, 313

Based on this simulation, what is the estimated probability that at least 2 of 3 randomly selected students are in band?

Enter your answer, as a decimal, in the box.

Answer 1

Answer: its 0.10

Explanation:

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Answer 2

0.45

Explanation:

1) the required probability can be calculated as:

P=(number_trials_with_2or3_students_in_band)/(total_number_trials);

according to the formula above:

2) number of trials with 2 or 3 students in the band is:

233, 113, 131, 244, 414,344, 412, 132, 554, 454,334, 235, 125, 412, 254,232, 221, 342, 333, 313 - 9;

3) total number of trials is: 20.

finally, P=9/20=0.45