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Almost a billion people on the planet don't have access to clean drinking water." if there were 7.2×109 people in the world in 2014, then approximately what percent of them lived without clean drinking water? round to the nearest tenth of a percent.

2 Answers

5 votes
13.9%.

7.2 x 10^9 = 7,200,000,000.

Since 1 billion = 1,000,000,000 out of these 7,200,000,000 do not have access to clean water, we find the percent by taking:
1,000,000,000/7,200,000,000 = 10/72 = 13.9%
User Access Denied
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6 votes

Answer: 13.9%

Explanation:

Given : Almost a billion people on the planet don't have access to clean drinking water."

We know that 1 billion =
1,000,000,000=10^9

There were
7.2*10^9 people in the world in 2014.

Now, the percent of people lived without clean drinking water :-


\frac{\text{Number of people lived without clean water}}{\text{Total people in the world}}*100\\\\=(10^9)/(7.2*10^9)*100\\\\=(1)/(7.2)*100\\\\=0.138888888889*100\\\\=13.8888888889\%\approx13.9\% \ \ \text{[Round to the nearest tenth of a percent]}

Hence, approximately 13.9% of them lived without clean drinking water.

User Kushal Shinde
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