Question

A girl sits on a tire swing and is pushed in a circular motion by her father. Her tangential speed is 2.8 m/s and the girl travels in a circle with a diameter of 4.0 m. What is the girls centripetal acceleration?

Answer 1

Formula: Ca=Vt^2/r

centripetal acceleration(Ca)= ?
tangential speed(Vt)= 2.8m/s
Radius(r)=2m

Substitute: Ca=2.8^2/2
Ca=3.92m/s^2

Answer 2

The girl's centripetal acceleration is 3.92 m/s².

Step-by-step explanation:

Given that,

Tangential speed = 2.8 m/s

Diameter = 4.0 m

We need to calculate the centripetal acceleration

Using formula of centripetal acceleration

`\alpha=(v^2)/(r)`

Where, v = tangential speed

r = radius

Put the value into the formula

`\alpha=(2.8^2)/(2.0)`

`\alpha=3.92\ m/s^2`

Hence, The girl's centripetal acceleration is 3.92 m/s².