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The quadratic equation y=-x^2+2x-3, the axis of symmetry is x=1. What is the vertex?

User Mspir
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1 Answer

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ANSWER


(1,-2)

Step-by-step explanation

The given quadratic equation is:


y = - {x}^(2) + 2x - 3

The axis of symmetry of this parabola is


x = 1

This is the also the x-coordinate of the vertex.

To find the y-coordinate of the vertex, substitute x=1 into the equation.


y = - {(1)}^(2) + 2(1)- 3


y = - 1 + 2 - 3


y = - 2

The vertex is

(1,-2)

User Claro
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