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If there is a solution I must put it down please help.

If there is a solution I must put it down please help.-example-1
User VenoMKO
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1 Answer

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17 votes

Explanation:

a). x-5 = -4

⇛x = -5+5

Therefore, x = 0 = 1

b). -8x - 2 = -8

⇛-8x = -8-2

⇛-8x = -10

⇛x = -10÷-8

⇛x = 10/8

Therefore, x = 5/4

c). 3x + 26 = 5x

⇛3x -5x = -26

⇛-2x = -26

⇛x = -26÷-2

⇛x = -26/-3

Therefore, x = 26/3

d). 12 = 4(-17+ 5x)

⇛12 = -68 + 20x

⇛12 +68 = 20x

⇛80 = 20x

⇛x = 20/80

Therefore, x = 1/4

e). x = (3/4)x -2

⇛ x -(3/4)x = -2

Therefore, x = 6

f). 0.5x + 4.75 = 13

⇛0.5x = 13-4.75

⇛0.5x = 8.25

⇛x = 8.25/0.5

Therefore, x = 16.5

g). 127.5 = 12x+(60/8)

⇛127.5 = 12x + (30/4)

⇛-12x = (30/4) - 127.5

⇛-12x = (30/4) - (127.5/1)

⇛-12x = (30*1 - 127.5*4)/4

⇛-12x = (30- 510)/4

⇛-12x = -480/4

⇛-12x = -240/2

⇛-12x = -120

⇛x = -120/-12

Therefore, x = 10

h). (1/7)(-20-4x)=-4

⇛(-20-4x)/7 = -4/1

⇛1(20-4x) =7 (-4)

⇛20 - 4x = -28

⇛-4x = -28-20

⇛-4x = -8

⇛x = -8/-4

Therefore, x = 2

i). -18 = x - 12

⇛-18 + 12 = x

⇛-6 = x

Therefore, x = -6

j). -7(2/3) = 4x-9

⇛-(21+2)/3 = 4x - 9

⇛-(23/3) = 4x -9

⇛-(23/3) + 9 = 4x

⇛-(23/3) + (9/1) = 4x

⇛-(23*1 + 9*3)/3 = 4x

⇛(-23 + 27)/3

⇛(4/3) = 4x

⇛(4/3)÷4 = x

⇛(4/3) × (1/4) = x

⇛(4*1)/(3*4) = x

⇛4/12 = x

Therefore, x = 4/12

l). -6(2.5x + 8) = -123

⇛-15x -48 = -123

⇛-15x = -123+ 48

⇛-15x = -75

⇛x = -75/-15

Therefore, x = 5

m). -19x = 100 + x

⇛-19x - x = 100

⇛-20x = 100

⇛x = 100/-20

Therefore, x = -5

n). 0.2x - 0.5 = 1.2

⇛0.2x = 1.2 + 0.5

⇛0.2x = 1.8

⇛x = 1.8/0.2

Therefore, x = 4

o). (-2)² - 3x = -17

⇛(-2*-2) - 3x = -17

⇛4 - 3x = -17

⇛-3x = -17-4

⇛-3x = -21

⇛x = -21/-3

Therefore, x = 7

p). -(1/2)x -(4/5) = 19/4

⇛-(1/2)x = (19/4) + (4/5)

Take the LCM of the denominator 4 and 5 is 20.

⇛-(1/2)x = (19*5 + 5*4)/20

⇛-(1/2)x = (95 + 16)/20

⇛-(1/2)x =111/20

⇛x = (111/20) + (1/2)

Again take the LCM of the denominator 20 and 2 is 20.

⇛x = (111*1 + 1*10)/20

⇛x = (111 + 10)/20

⇛x = (121/20)

Therefore, x = 121/20

q). (x/8) + 2 = 1/4{(5/16) + 8}

⇛(x/8) + 2 = (5/64) + 2

⇛(x/8) + 2 = (5/64) + (2/1)

Take the LCM of the denominator 1 and 64 is 64 in RHS.

⇛(x/8) +2 = (5*1 + 2*64)/64

⇛(x/8) + 2 = (5 + 128)/64

⇛(x/8) + 2 = 133/64

⇛x/8 = (133/64) - 2

⇛x/8 = (133/64) - (2/1)

Take the LCM of the denominator 1 and 64 is 64 in RHS.

⇛x/8 = (133*1 - 2*64)/64

⇛x/8 = (133 - 128)/64

⇛x/8 = 5/64

On applying cross multiplication, then

⇛x(64) = 8(5)

⇛64x = 40

⇛x = 40/64

⇛x = (40÷4)/(64÷4)

⇛x = 10/12

⇛x = (10÷2)/(16÷2)

Therefore, x = 5/8

r). -6 = -3{(1/7)x + (4/14)}

⇛-6 = -(3/7)x -(6/7)

⇛-6 + (6/7) = -(3/7)x

⇛-(6/1) + (6/7) = -(3/7)x

Take the LCM of the denominator 1 and 7 is 7 in LHS.

⇛(-6*7 + 6*1)/7 = -(3/7)x

⇛(-42 + 6)/7 = -(3/7)x

⇛-(36/7) = -(3/7)x

On applying cross multiplication, then

⇛7(36) = 21x

⇛252 = 21x

⇛252/21= x

⇛12 = x

Therefore, x = 12

s). (1/4)x = 11/4

⇛x = (11/4) - (1/4)

⇛x = (11-1)/4

⇛x = 10/4

⇛(10÷2)/(4÷2)

Therefore, x = 5/2

t). x - (-3) = 9

⇛x + 3 = 9

⇛x = 9-3

Therefore, x = 6.

Please let me know if you have any other questions.

User Alex Spangher
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