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Comppete the equation
X^2+y^2-10x+6y=15

User Vine
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1 Answer

4 votes
I believe you meant: Use completing the square to determine the center and radius of the circle represented by this equation: X^2+y^2-10x+6y=15

x^2 - 10x + 25 - 25 + y^2 + 6y + 9 - 9 = 15
Then:
(x-5)^2 + (y+3)^2 = 24 = 2sqrt(6)

This circle is centered at (5,-3) and has radius 2sqrt(6).
User Giacomo Penuti
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