Question

write the equation of a line that passes through the point (9,-2) and is parallel to the line y+1=2(x-3)

Answer 1

y = 2x - 20

Explanation:

Equation of line: y =mx +b

where m is slope and b is y-intercept.

y + 1 = 2(x - 3)

Write this equation in y = mx + b form.

y + 1 = 2x - 2*3

y + 1 =2x - 6

y = 2x - 6 - 1

y = 2x - 7

m =2

Parallel lines have same slope.

Slope of the required line = 2

y = 2x + b

The point (9,-2) passes through the line. Substitute in the above equation and find the value of 'b'.

-2 = 9*2 + b

-2 = 18 + b

-2 - 18 = b

`\sf \boxed{b = -20}`

Equation of the required line:

y = 2x - 20