Question

A ball whose mass is 0.3 kg hits the floor with a speed of 7 m/s and rebounds upward with a speed of 4 m/s. if the ball was in contact with the floor for 1.5 ms (1.5multiply10-3 s), what was the average magnitude of the force exerted on the ball by the floor? favg = 602.94 incorrect: your answer is incorrect. n.

Answer 1

Newton's second law is stated as:
F=ma,

a = (7-4)/1.5 = 2 m/s^2 (it is a deceleration due to impact with floor. And thus the ball exerts force on the floor).

Therefore,

F= 0.3*2 = 0.6 N