Question

A TtYy pea plant self-pollinates and one seed is picked at random for planting. (a) What is the chance that the seed will produce a tall, green seeded pant? (b) If it turn out to be tall and yellow seeded what is the chance that its genotype is TTYY.

Answer 1

a) The chances a seed when a TtYy pea plant self pollinates, the seed will produce a tall and green seedling is 18.75%

b) The chances a seed when a TtYy pea plant self pollinates, the seed is Homozygous tall and yellow pea plant is only 6.25%.

Step-by-step explanation:

a) A tall, green seeded plant could have the genotypes of either be Ttyy or TTyy. So when we write a punnet square:

You will realize Ttyy appears 2 times and TTyy, one time. This means 3 out of the 16 possibilities will lead to a a tall green seedling. When 3/16 is converted in a percentage, it is 18.75%. Therefore, when a TtYy pea plant self-pollinates, there is a 18.75% chance of getting a tall green, pea plant.

b) A tall, homozygous, yellow pea plant must have the genotypes of TTYY, which only appears once. This means only 1 out of the 16 possibilities will lead to a a tall yellow seedling. So when 1/16 is converted into a percentage, it is 6.25%. Therefore, when a TtYy pea plant self-pollinates, there is a 6.25% chance of getting a tall, yellow, homozygous pea plant.