Question

What are they intercepts of y=2x^2-3x-20 a)x=-5 and 2 b)x=5 and -2 c)x=-2.5 and 4 d)x=2.5 and -4

Answer 1

x-intercept: Set y= 0 and find x. Then 2x^2-3x-20= 0. You must find the roots; there will be two real, unequal roots. The x-intercepts will look like (a,0) and (b,0), where a and be are your two real, unequal roots.

y-intercept: set x=0. Then 2(0)^2 - 3(0) - 20 = -20. The y-int. is (0,-20).