Question

I'm stuck!.. if u think u can help me please do!!!

Answer 1

we'll first conver the mixed fraction to "improper".

for A) is very simple, is just the difference of both.

for B) is the difference of 9 innings and what has been pitched already.


`\bf \stackrel{mixed}{1(2)/(3)}\implies \cfrac{1\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{5}{3}} \\\\\\ A)\\\\ \stackrel{start~pitcher}{5}-\stackrel{relief~pitcher}{\cfrac{5}{3}}\quad \stackrel{LCD~of~3}{\implies }\quad \cfrac{15-5}{3}\implies \cfrac{10}{3}\implies 3(1)/(3) \\\\\\ B)\\\\ 9-\left( 5+\cfrac{5}{3} \right)\implies 9-\left( \cfrac{15+5}{3} \right)\implies 9-\cfrac{20}{3} \\\\\\ \textit{LCD of 3}\qquad \cfrac{27-20}{3}\implies \cfrac{7}{3}\implies 2(1)/(3)`