213k views
2 votes
You plant a rectangular rose garden along the side of your garage. You enclose 3 sides of the garden with 40 feet of fencing. The total area of the garden is 100 square feet. Find the possible dimensions of the garden.

1 Answer

4 votes

Let's assume

length of rectangle =L

width of rectangle =W

You enclose 3 sides of the garden with 40 feet of fencing

so, we get


L+2W=40

now, we can solve for L


L=40-2W

we know that

area of rectangle is


A=L*W


100=L*W

now, we can plug


100=(40-2W)*W

now, we can solve for W


-2W^2+40W-100=0

we can use quadratic formula


W=(-40+√(40^2-4\left(-2\right)\left(-100\right)))/(2\left(-2\right))


W=(-40-√(40^2-4\left(-2\right)\left(-100\right)))/(2\left(-2\right))

we can take anyone value ..because both are giving positive value

first dimensions:


W=2.929

now, we can find L


L=40-2*2.929


L=34.142

so, length is 34.142feet

width is 2.929 feet

Second dimensions:


W=17.071

now, we can find L


L=40-2*17.071


L=5.858

so, length is 5.858feet

width is 17.071 feet



User Hud
by
8.1k points