Question

LOOK AT PICTURE

a rectangular classroom is 32 feet long and has a perimeter of 120 feet. Label The drawing with the correct values to represent the situation. Let w represent the width of the classroom.

Answer 1

Expression 120= (32*2)+(X*2)
Expression: (32+W)*2=12
Expression: p=(l*2)+(w*2)
Width: 28

Answer 2

the sum of the length and the width = L +W

Twice the sum of the length and the width = 2L+2W

Perimeter = P = 2L+2W

W idth=28 feet

Explanation:

Hi, the sum of the length and the width = L +W

Twice the sum of the length and the width = 2L+2W

Perimeter = P = 2L+2W

Where L is the length and W the width.

Value of the width.

Using the perimeter formula and replacing width the values given:

120 = 2 (32) + 2 W

120 = 64 +2W

120-64 = 2W

56=2W

56/2=W

28 feet =W

Feel free to ask for more if needed or if you did not understand something.