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A 69.1-g sample of h2o contains how many molecules of water?

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The number of molecules of water is calculated as follows

find the moles of water= moles=mass/molar mass

moles = 69.1g/18 g/mol = 3.84 moles
by use of Avogadro law constant
that is 1 mole = 6.02 x10^23 molecules what about 3.84 moles of water

the molecules of water = (3.84 x 6.02 x10^23) = 2.312 x10^24 molecules
User Richard Topchii
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