Hello!
(Missing Previous Enunciate)
Use the Henderson-Hasselbalch equation to find the pH of:
To solve this question we need the pKa of HCOOH, which is 3,75, now, we can apply the Henderson-Hasselbach equation:
![pH=pKa+ log( ([HCOONa])/([HCOOH]) )=3,75 + log( (0,11M)/(0,17M) )=3,56](https://img.qammunity.org/2019/formulas/chemistry/college/63tqdg2ezuns4uu7xp2g371qf2urrwm4yi.png)
So, the pH of a solution that is 0,17 M in HCHO₂ and 0,11 M in NaCHO₂ is 3,56
Have a nice day!