Question

g(x) = x3 + 6x2 + 12x + 8 Determine the function’s value when x = −1. g(−1) = −3 g(−1) = 0 g(−1) = 1 g(−1) = 27

Answer 1

The correct answer is that g(-1) = 1.

To do this problem, we have to plug in -1 for x and evaluate the expression.

g(-1) = x^3 + 6x^2 + 12x + 8

(-1)^3 + 6(-1)^2 + 12(-1) + 8

-1 + 6 -12 + 8

1

Answer 2

option c, g (-1) = 1

Explanation:

The given function is g(x) = x³ + 6x² + 12x + 8

and we have to find the value of the function when x (-1) for this we will plug in the value of x = -1 in the function.

g (-1) = (-1)³ + 6 (-1)² + (12) (-1) + 8

= (-1) + 6 - 12 + 8

= 14 - 13

= 1

Therefore, option c, g (-1) = 1 will be the answer.