Question

If a sample of oxygen occupies a volume of 2.15 L at a pressure of 58.0 Kpa and a temperature of 25°C what volume of the sample a company at 101.3 K PA and 0°C

Answer 1

1.13 L

Step-by-step explanation:

Given data

• Initial pressure (P₁): 58.0 kPa

• Initial volume (V₁): 2.15 L

• Initial temperature (T₁): 25°C + 273.15 = 298 K

• Final pressure (P₂): 101.3 kPa

• Final volume (V₂): ?

• Final temperature (T₂): 0°C + 273.15 = 273 K

We can find the final volume of the oxygen gas using the combined gas law.

`(P_(1)* V_(1))/(T_(1)) =(P_(2)* V_(2))/(T_(2))\\(58.0kPa* 2.15L)/(298K) =(101.3kPa* V_(2))/(273K)\\V_(2)=1.13L`

Answer 2

The volume of the sample a company at 101.3 KPa and o degrees is calculated as follows

by use combined gas law

that is P1V1/T1= P2V2/T2

V2 = P1V1T2/T1P2

T1= 25 +273 = 298 K
P1= 58 kpa
V1= 2.15 L
P2= 101.3 kpa
T2 = o+273 = 273k
v2=?

V2= (58 x2.15 x273)/(298 x101.3) = 1.13 L