Question

For a particular reaction, δh = 120.5 kj and δs = 758.2 j/k. calculate δg for this reaction at 298 k.

Answer 1

Data Given:
Change in Entropy = ΔH = 120.5 kJ = 1.20 × 10⁵ J

Temperature = T = 298 K

Change in Entropy = ΔS = 758.2 J/K

Using Formula,
ΔG = ΔH - T ΔS
Putting Values,
ΔG = (1.20 × 10⁵ J) - (298 K × 758.2 J/K)

ΔG = -1.059 × 10⁵ J

ΔG = -105.94 kJ