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Write an equation of a circle with the given center and radius.center (4, 5), radius 7

User Jim Lynn
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Quadratic relations and comic sections unit test part 1

6. b. (x-4)^2 + (y-5)^2 = 49

User Trist
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To solve this, we are going to use the center-radius form of a circle equation:
(x-h)^(2)+(y-k)^(2)=r^(2)
where

(h,k) is the center of the circle

r is the radius of the circle

Since the center of our circle is
(4,5),
h=4 and
k=5. We also now that its radius is 7, so
r=7. Lets replace those values in our equation:

(x-h)^(2)+(y-k)^(2)=r^(2)

(x-4)^(2)+(y-5)^(2)=7^(2)

We can conclude that the equation of a circle with center at the point (4,5) and radius 7, is
(x-4)^(2)+(y-5)^(2)=7^(2)

User Pete Schlette
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