Ethene on combustion reaction produces CO₂ and H₂O,
C₂H₄ + 3 O₂ → 2 CO₂ + 2 H₂O
According to Equation,
28.05 g (1mole) C₂H₄ produced = 88 g (2 mole) of CO₂
So,
100 g of C₂H₄ will produce = X g of CO₂
Solving for X,
X = (100 g × 88 g) ÷ 28.05 g
X = 313. 72 g of CO₂