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Kx-3y=4 4x-5y=7 In the system of equations above, k is a constant and x and y are variables. For what value of k with a symptom of equation have no solution? A)12/5 B)16/7 C)-16/7 D)-12/5
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2 votes
Kx-3y=4

4x-5y=7
In the system of equations above, k is a constant and x and y are variables. For what value of k with a symptom of equation have no solution?

A)12/5
B)16/7
C)-16/7
D)-12/5

User Egy Mohammad Erdin
by
6.4k points

1 Answer

4 votes
To solve this problem, you need to recognize that the ratios of the coefficients must be equal. So the ratio for this system would be k/4 = -3/-5. Solving for k we get k = (3)*(4)/5 = 12/5, hence the answer is A. Hope that helps!
User Franky McCarthy
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