Question

What are the zeros Of the function f(x)=(x^2-9)(x+1?

Answer 1

`f(x) = (x^2 - 9)(x +1)`

when f(x) = 0,


`(x^2 - 9)(x +1) = 0`


`(x - 3)(x+3)(x +1) = 0`


`(x - 3) = 0 \text { or } (x+3)= 0 \text { or } (x +1) = 0`


`x = 3 \text { or } x= -3 \text { or } x= -1`


The graph cuts the y-axis at (3, 0), (-3, 0) and (-1, 0)