Question

A solution was prepared by dissolving 26.0 g of kcl in 225 g of water.calculate the mole fraction of the ionic species kcl in the solution.

Answer 1

The mole fraction of KCl in the solution is calculated by dividing the moles of KCl by the total moles of KCl and water, resulting in a mole fraction of approximately 0.0272.

Step-by-step explanation:

The question is asking to calculate the mole fraction of KCl (potassium chloride) in a solution. The first step is to determine the number of moles of KCl and water. With a molecular weight of approximately 74.55 g/mol for KCl, and 26.0 g of KCl, we calculate the moles of KCl as:

moles of KCl = 26.0 g / 74.55 g/mol = 0.349 moles of KCl.

The molecular weight of water (H2O) is approximately 18.015 g/mol, converting 225 g of water to moles gives:

moles of water = 225 g / 18.015 g/mol = 12.49 moles of water.

The mole fraction for a component in a mixture is the number of moles of that component divided by the total number of moles of all components. Therefore, the mole fraction of KCl is:

mole fraction of KCl = moles of KCl / (moles of KCl + moles of water)

= 0.349 / (0.349 + 12.49)

= 0.349 / 12.839

= 0.0272 (approx).

The mole fraction of KCl in the solution is therefore approximately 0.0272.

Answer 2

Mole fraction of components in a mixture can be calculated as follows;
Mole fraction of KCl = number of moles of KCl / (KCl moles + H₂O moles)
mass of KCl dissolved - 26.0 g
Molar mass of KCl - 74.5 g/mol
Number of KCl moles - 26.0 g/74.5 g/mol = 0.35 mol
Mass of water - 225 g
Molar mass of water - 18 g/mol
Number of water moles - 225 g /18 g/mol = 12.5 mol
total number of moles in the mixture - 0.35 + 12.5 = 12.85

Mole fraction of KCl -
`(0.35 mol)/(12.85mol)`
mole fraction KCl - 0..027