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Find the zeros of f(x) = (x -3)^2 - 49
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Find the zeros of f(x) = (x -3)^2 - 49

User Uranibaba
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1 Answer

3 votes
We have the function f(x)=(x-3)^2-49.
This equals...
0 = (x-3)^2 - 49
Add 49.
49 = (x-3)^2
Square both sides.
±7 = x-3
± 10 = x
User Rauly
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