Question

For the function f(t) = Pe^rt, if P= 3 and r = 0.03 what is the value of f(3) to the nearest tenth? A: 2.5 B: 3.3 C: 7.4 D: 1.1

Answer 1

B, You plug in the numbers like 3e^(3*.03) for 3.3

Answer 2

B. 3.3

Explanation:

We have been given a function
`f(t)=Pe^(rt)`. We are asked to find the value of f(3), when
`P=3\text{ and }r=0.03`.

Upon substituting our given values our function would be
`f(t)=3e^(0.03t)`.

To find f(3), we will substitute
`t=3` in our given function as:

`f(3)=3e^(0.03*3)`

`f(3)=3e^(0.09)`

`f(3)=3*1.0941742837052104`

`f(3)=3.2825228511156312`

`f(3)\approx 3.3`

Therefore, the value of
`f(3)` is approximately 3.3 and option B is the correct choice.