Question

A spinner used for a game is divided into 3 sections: yellow, green, and orange. Janie spins the spinner 20 times. The spinner lands on green 8 times. What is the experimental probability that the spinner does NOT land on green?

Answer 1

2/3 is the answer. Try not to overthink these answers because they’re usually quite simple in the end. :)

Answer 2

Answer:
`(3)/(5)`

Explanation:

Given : A spinner used for a game is divided into 3 sections: yellow, green, and orange.

Janie spins the spinner 20 times.

The spinner lands on green 8 times.

It means , the number of times it does not land on green section = 20-8=12

Then, the experimental probability that the spinner does NOT land on green :-

`\text{P(green)}=\frac{\text{Number of times spinner does not land on green}}{\text{Total number of times spinner spins}}\\\\=(12)/(20)=(3)/(5)`

∴ Required probability =
`(3)/(5)`