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Given cosx=12/13 and sinx=5/13 . What is ratio for ​ tanx ​ ? Enter your answer in the boxes as a fraction in simplest form.

2 Answers

3 votes
Remember that
tangent = (sine)/(cosine).

Since you know
cosx = (12)/(13) and
sinx = (5)/(13),
tanx = (sinx)/(cosx). Plug the values you're given into that equation to find tanx. Remeber that dividing by a fraction is the same thing as multiplying the inverse of that fraction (aka the fraction flipped):

tanx = (sinx)/(cosx) \\ tanx = ((5)/(13))/( (12)/(13)) \\ tanx = (5)/(13) * (13)/(12)\\ tanx = (5)/(12)

Your answer is tanx = 5/12.

You could also do this problem by drawing a right triangle, picking an angle that is not the right angle, and filling in the values of the sides, knowing SOHCAHTOA:

sin\theta = (opposite)/(hypotenuse) \\ cos\theta = (adjacent)/(hypotenuse) \\ tan\theta = (opposite)/(adjacent)

User Davzaman
by
6.2k points
7 votes

Answer:

5/12

Explanation:

Took the test

Given cosx=12/13 and sinx=5/13 . What is ratio for ​ tanx ​ ? Enter your answer in-example-1
User Bgi
by
7.1k points
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