Question

A can of soup is in the shape of a cylinder. The diameter of the can is 8 centimeters, and the height is 10 centimeters. What is the surface area of the can, rounded to the nearest hundredth square centimeter? (Use 3.14 for π.) 351.68 cm 2 251.2 cm 2 502.4 cm 2 100.48 cm 2

Answer 1

351.68 is ur answer

Explanation:

Answer 2

The surface area of the can is
`351.68\ cm^(2)`

Explanation:

we know that

The surface area of a cylinder (can of soup) is equal to

`SA=2\pi r^(2)+\pi Dh`

we have

`r=8/2=4\ cm` ----> the radius is half the diameter

`D=8\ cm`

`h=10\ cm`

substitute the values

`SA=2(3.14)(4^(2))+(3.14)(8)(10)`

`SA=100.48+251.2=351.68\ cm^(2)`