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In si units, the electric field in an electromagnetic wave is described by ey = 104 sin(1.40 107x − ωt). (a) find the amplitude of the corresponding magnetic field oscillations. µt (b) find the wavelength λ. µm (c) find the frequency f.

User That Marc
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1 Answer

5 votes
Answers:
(a)
B_o  = 0.3466μT
(b)
\lambda = 0.4488μm
(c) f =
6.68 * 10^(14)Hz

Step-by-step explanation:
Given electric field(in y direction) equation:

E_y = 104sin(1.40 * 10^7 x -\omega t)

(a) The amplitude of electric field is
E_o = 104. Hence

The amplitude of magnetic field oscillations is
B_o = (E_o)/(c)
Where c = speed of light

Therefore,

B_o = (104)/(3*10^8) = 0.3466μT (Where T is in seconds--signifies the oscillations)

(b) To find the wavelength use:

(2 \pi )/(\lambda) = 1.40 * 10^7

\lambda = (2 \pi)/(1.40) * 10^(-7)

\lambda = 0.4488μm

(c) Since c = fλ
=> f = c/λ

Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f =
6.68 * 10^(14)Hz


User Vinayak Hegde
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