Final answer:
The electrical energy expended by a 5.0 ohm resistor with a current of 2.4 amperes for one second is 28.8 joules.
Step-by-step explanation:
To calculate the amount of electrical energy expended by the 5.0 ohm resistor when a current of 2.4 amperes passes through it, we use the formula for power (P = I2R) and then use the energy formula (E = P*t). Assuming we are dealing with a time period of one second for convenience:
P = I2R = (2.4 A)2(5.0 Ω) = 28.8 W (watts).
Then, the electrical energy (E) expended in one second (which is equal to the power, since power is the rate at which energy is used per unit time) is:
E = P*t = 28.8 W * 1 s = 28.8 J (joules).
The electrical energy expended by the 5.0 ohm resistor with a current of 2.4 amperes is 28.8 joules.