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A bubble of helium gas has a volume of 0.650 ml near the bottom of a large aquarium where the pressure is 1.54 atm and the temperature is 12°c. determine the bubble's volume upon rising near the top where the pressure is 1.01 atm and 16°c. assume that the number of moles of helium remains constant and that the helium is an ideal gas.

User Ejaenv
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1 Answer

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For this question we can use the combined gas law equation.

(PV)/(T) = k for a fixed amount of gas
where P - pressure , V - volume , T- temperature and k - constant

(P1V1)/(T1) = (P2V2)/(T2)
Where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
temperature in K
T1 = 12 °C + 273 = 285 K
T2 - 16 °C + 273 = 289 K
substituting the values in the equation

(1.54 atm * 0.650 mL )/(285K) = (1.01 atm*V)/(289K)
V = 1.00 mL

User GlassGhost
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