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Algebra Nation! Please Help

Algebra Nation! Please Help-example-1

2 Answers

4 votes

Answer:

The distance Yochanan covered by walking is 5 miles.

Explanation:

Given: The system of equations

5x + 60y = 35

and x + y = 1.5

We have to determine the distance Yochanan covered by walking.

Consider the given system of linear equation.

5x + 60y = 35

and x + y = 1.5

Where x represents the time he takes to cover walking distance.

and y represents the time taken by school bus.

We need to find x,

Consider the system

5x + 60y = 35 ...........(1)

x + y = 1.5 ..........(2)

Using elimination method to solve the given system.

Multiply equation (2) by 60

(2) ⇒ 60x + 60y = 90 ..........(3)

Subtract (1) from (3) , we have,

60x + 60y -(5x+ 60 y ) = 90 - 35

⇒ 55x = 55

⇒ x = 1

Thus, He took 1 hours walking.


Speed=(Distance)/(time)

Given : speed = 5 miles per hour

time = 1 hour

So, Distance = 5 miles per hour × 1 hour = 5 km.

Thus, The distance Yochanan covered by walking is 5 miles.

User Ross Riley
by
7.8k points
3 votes
For this case we have the following system of equations:

5x + 60y = 35 x + y = 1.5
Where,
x: time in hours walking
Y: time in hours on the bus
We solve the system of equations.
Rewriting the system we have:

5x + 60y = 35 -60x -60y = -90
Adding both equations we have:

-55x = -55
Clearing x we have:

x = -55 / -55 x = 1
Then, the number of Yochanan road miles is:

5x = 5 (1) = 5
Answer:
Yochanan walked about:
5 miles
User Rxdazn
by
8.0k points