Calculate the magnitude of the angular momentum of the earth due its daily rotation about its own axis

asked Nov 18, 2019 176k views

1 vote

by Mplis

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$I_(earth) = (2)/(5) r^(2)m= (2)/(5) (6371000^2m)(5.97*10^(24)kg)=9.71*10^ {37}$

$L_(earth)=Iw=(9.71*10^ {37})(7.27*10^(-5))=7.07*10^(33)$ [/tex]

Akshay Mohite answered Nov 25, 2019

9.3k points

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